FDOT Standard Plans Index 450-511: Bearing Plates (Type 1) - Prestressed Florida - I & AASHTO Type II Beams

Design Criteria

Design Criteria AASHTO LRFD Bridge Design Specifications ; Structures Design Guidelines ( SDG )

Design Assumptions and Limitations

Design Assumptions and Limitations This standard is intended for use on bridge widenings (with or without end diaphragms) where squared end beams are not feasible as determined by the EOR. For all other cases, use Index 45 0 - 512 and its Instructions. Index 45 0 - 512 may be used for all projects with squared end beams, with or without end diaphragms.

This standard contains generic details and notes for beveled and embedded bearing plates for prestressed concrete Florida - I and AASHTO Type II Beams with or without skewed end conditions. Use this standard with Indexes 45 0 - 010, 45 0 - 036, 45 0 - 045, 45 0 - 054, 45 0 - 063, 45 0 - 072, 45 0 - 078, 45 0 - 084, 45 0 - 096, 45 0 - 120 and 40 0 - 510. Embedded Bearing Plates A are required for all Florida - I Beams (FIBs).

Embedded Bearing Plates A and Beveled Bearing Plates B are required for beams on grades greater than 2%. Embedded Plates A are cast into the beams 1½" from the beam ends. The position of the centerline of Beveled Plates B is dependent on the presence or absence of end diaphragms, ensuring the minimum bearing length for LRFD seismic requirements is satisfied.

Payment

Payment The cost of beveled and embedded bearing plates is incidental to the cost of the prestressed beams they are used with. No separate payment is made. Standard Plan s Instructions Topic No.

625 - 010 - 003 Index 450 - 511 Bearing Plates (Type 1) - Prestressed Florida - I & AASHTO Type II Beams Example A design calls for FIBs with Type F Bearing Pads. The Grade along the PGL and centerline of the beam is negative 2.5% and slope due to camber and deflection is less than 0.0125 radians. The span has a skew of 10°.

Because the slope is greater than the absolute value of 2%, beveled bearing plates are required. From Index 40 0 - 510 a Type F Bearing Pad is 10" x 2' - 8", and the Beveled Bearing Plate (Plate B) has dimensions C = 1' - 0" and D = 3' - 0". The bridge has a 10° skew (Φ=80°).

From Index 45 0 - 010 using Case 2, End Condition 3 formulas: END 1 END 2 W=0.5" W=0.5" - ((12"/sin(80°)*( - 0.025)) = 0.805" X=0.5" - ((36"/tan(80°)*( - 0.025)) = 0.659" X=0.5" - ((12"/sin(80°)+36"/ tan(80°))*( - 0.025))=0.963" Y=0.5" - ((12"/sin(80°)+36"/ tan(80°))*( - 0.025))=0.963" Y= 0.5" - ((36"/tan(80°)*( - 0.025)) = 0.659" Z=0.5" - ((12"/sin(80°)*( - 0.025)) = 0.805" Z= 0.5" Complete the Table with location information and the following from the example:

What your plans must show

Plan Content Requirements for this index — the SPI's checklist for designers.

• Standard Plan s Instructions Topic No. 625
• - 511 Bearing Plates (Type 1)
• 120. The Slope parameter in these equations requires decimal units and correct sign convention:
• Standard Plan s Instructions Topic No. 625
• - 511 Bearing Plates (Type 1)
• - I & AASHTO Type II Beams END 1 END 2 (I) PLAN VIEW CASE 1: (a) END ELEVATION CONDITION 1 or 2 (Positive Slope) W = X = 0.5" + (C) x Slope W = X = 0.5" Y = Z = 0.5" Y = Z = 0.5" + (C) x Slope (b) END ELEVATION CONDITION 1 or 3 (Negative Slope) W = X = 0.5" W = X = 0.5"
• - (C) x Slope Y = Z = 0.5"
• - (C) x Slope Y = Z = 0.5" (II) PLAN VIEW CASE 2: (a) END ELEVATION CONDITION 1 or 2 (Positive Slope) W = 0.5" + (C / sin Φ + D / tan Φ) x Slope W = 0.5" + (D / tan Φ) x Slope X = 0.5" + (C / sin Φ) x Slope X = 0.5" Y = 0.5" Y = 0.5" + (C / sin Φ) x Slope Z = 0.5" + (D / tan Φ ) x Slope Z = 0.5" + (C / sin Φ + D / tan Φ) x Slope (b) END ELEVATION CONDITION 1 or 3 (Negative Slope) W = 0.5" W = 0.5"
• - (C / sin Φ) x Slope X = 0.5"
• - (D / tan Φ) x Slope X = 0.5"
• - (C / sin Φ + D / tan Φ) x Slope Y = 0.5"
• - (C / sin Φ + D / tan Φ) x Slope Y = 0.5"
• - (D / tan Φ) x Slope Z = 0.5"
• - (C / sin Φ) x Slope Z = 0.5" (III) PLAN VIEW CASE 3: (a) END ELEVATION CONDITION 1 or 2 (Positive Slope) W = 0.5"+ (C / sin Φ) x Slope W = 0.5" X = 0.5" + (C / sin Φ + D / tan Φ) x Slope X = 0.5" + (D / tan Φ) x Slope Y = 0.5" + (D / tan Φ) x Slope Y = 0.5" + (C / sin Φ + D / tan Φ) x Slope Z = 0.5" Z = 0.5" + (C / sin Φ) x Slope (b) END ELEVATION CONDITION 1 or 3 (Negative Slope) W = 0.5"
• - (D / tan Φ) x Slope W = 0.5"
• - (C / sin Φ + D / tan Φ) x Slope X = 0.5" X = 0.5"
• - (C / sin Φ) x Slope Y = 0.5"
• - (C / sin Φ) x Slope Y = 0.5" Z = 0.5"
• - (C / sin Φ + D / tan Φ) x Slope Z = 0.5"
• - (D / tan Φ) x Slope For all cases: E = C / sin Φ G = 13.5” / sin Φ
• Standard Plan s Instructions Topic No. 625
• - 511 Bearing Plates (Type 1)
• - I & AASHTO Type II Beams